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An inductor (L = 100 mH), a resistor `(R = 100Omega)` and a battery (E = 100 V) are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the points A and B. The current in the circuit 1 ms after the short circuit is A. eAB. 0.1AC. 1AD. 1/eA |
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Answer» Correct Answer - D During decay of current, `i=i_(0)e^(-(Rt)/(L))=(E)/(R)e^(-(Rt)/(L))=(100)/(100)e^((100xx10^(-3))/(100xx10^(-3)))=(1)/(e)A` |
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