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An inductance `L` and and a resistance `R` are connected in series to a battery of voltage `V` and negligible internal resistance through a switch. The switch is closed at `t = 0`. The charge that passes through the battery in one time constant is [`e` is base of natural logarithms]A. `(e R^(2)V)/(L)`B. `(VL)/(R )`C. `(VL)/(eR^(2))`D. `(eL)/(VR)` |
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Answer» Correct Answer - C `q = int i dt = int i_(0)(1-e^((-R )/(L)t))dt` |
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