An inductance `L` and a resistance `R` are first connected to a battery. After some time the battery is disconnected but `L` and `R` remain connected in a closed circuit. Then the current reduces to `37%` of its initial value inA. RL secondB. `(R)/(L)`secondC. `(L)/(R)`secondD. `(1)/(LR)`second

An inductance `L` and a resistance `R` are first connected to a batter

1.	An inductance `L` and a resistance `R` are first connected to a battery. After some time the battery is disconnected but `L` and `R` remain connected in a closed circuit. Then the current reduces to `37%` of its initial value inA. RL secondB. `(R)/(L)`secondC. `(L)/(R)`secondD. `(1)/(LR)`second
Answer» Correct Answer - C Time constant, `tau=(L)/(R)` It is the time interval during which the current after opening an inductive circuit falls to `37%` of its maximum value.

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An inductance `L` and a resistance `R` are first connected to a battery. After some time the battery is disconnected but `L` and `R` remain connected in a closed circuit. Then the current reduces to `37%` of its initial value inA. RL secondB. `(R)/(L)`secondC. `(L)/(R)`secondD. `(1)/(LR)`second

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