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An inductance `L` and a resistance `R` are first connected to a battery. After some time the battery is disconnected but `L` and `R` remain connected in a closed circuit. Then the current reduces to `37%` of its initial value inA. `RL sec`B. `(R )/(L)`secC. `(L)/(R )`secD. `(1)/(LR)`sec |
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Answer» Correct Answer - C When battery disconnected current through the circuit start decreasing exponentially according to`i=i_(0)e^(-Rt//L)`. `implies0.37i_(0)=i_(0)e^(-Rt//L)implies0.37=(1)/(e)=e^(-Rt//L)impliest=(L)/(R )` |
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