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An incompressible fluid flows steadily through a cylinder pipe which has 2r at point A and radius r at B further along the flow direction. If the velocity at point A is v, its velocity at point B isA) 2v B) v C) v/2 D) 4v |
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Answer» D) 4v Explanations: At point A, radius is 2r and at point B, radius is r. Area × velocity = constant Hence πr 2 × V = constant i.e. r1 2V1 = r2 2V2 Given r1 = 2r r2 = r V1 = V V2 =? ∴ (2r)2 × V = r2 ∙ V2 ∴ V2 = 4V V2 means velocity at point B i.e. V-B = 4V |
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