An ideal solution of two liquids is a solution in which each component obeys Raoult's which states that the vapour pressure of any component in the solution depends on the mole fraction of that component in the solution and the vapour pressure of that component in the pure state. However, there are many solution which do not obey Raoult's law. In other words, they show deviations from ideal behaviour which may be positive or negative. However, in either case, corresponding to a particular composition, they form a constant boiling mixtures called azeotropes. A solution has a 1:4 mole ratio of pentane to hexane. The vapour presssures of the pure hydrocarbons at 20^(@)C are 440 mm of Hg for pentane and 120 mm of Hg for hexane. The mole fraction at pentane in the vapour phase would be

An ideal solution of two liquids is a solution in which each component

1.	An ideal solution of two liquids is a solution in which each component obeys Raoult's which states that the vapour pressure of any component in the solution depends on the mole fraction of that component in the solution and the vapour pressure of that component in the pure state. However, there are many solution which do not obey Raoult's law. In other words, they show deviations from ideal behaviour which may be positive or negative. However, in either case, corresponding to a particular composition, they form a constant boiling mixtures called azeotropes. A solution has a 1:4 mole ratio of pentane to hexane. The vapour presssures of the pure hydrocarbons at 20^(@)C are 440 mm of Hg for pentane and 120 mm of Hg for hexane. The mole fraction at pentane in the vapour phase would be
Answer» 0.2 0.478 0.549 0.786 Solution :`x_("PENTANE")=(1)/(5)=0.2, x_("HEXANE")=0.8` `p_("pentane")=0.2xx"440 mm = 88 mm"` `p_("hexane")=0.8xx"120 mm = 96 mm"` `therefore"Mole fraction of pentane in VAPOUR PHASE "` `=(88)/(88+96)=0.478`