1.

An ideal gaseous sample at initial state I (P_0, V_0, T_0) is allowed to expand to volume 2V_0 using two different process, in the first process the equation of process is PV_2=K_1 and in second process the equation of the process is PV=K_2.Then

Answer»

Work done in first process will be greater than work in a second process (MAGNITUDE wise)
The order of values of work done can not be compared unless we know the value of `K_1` and `K_2`
Values of work done (magnitude) in second process in greater in above expansion IRRESPECTIVE of the value of `K_1` and `K_2`
`I^(ST)` process is not possible

Solution :Work done is isothermal process will be more than `PV^2`=const. process WHATEVER whatever be the value of `K_1 and K_2`


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