1.

An ideal gas with density 6 gm//L has a pressure of 38 torr at room temperature, then calculate the value of root mean square speed (in m/sec) of molecules of this gas. [Take 1 atm = 10^(5) Pascal] [Divide your answer by 10]

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Solution :`U_("rms") = sqrt((3RT)/(M)) = sqrt((3P)/(d)) = sqrt((3 xx 38 xx 10^(5))/(760 xx 6)) = sqrt((10^(4))/(4))` where `d = 6 gm//"LIT". = 6 xx 10^(-3) kg//10^(-3) m^(3) = 6 kg//m^(3)`
`U_("rms") = (100)/(2) = 50 m//sec`
`= (50)/(10) = 5`


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