An ideal gas is initially at temperature T and volume V. Its volume increases by DV due to an increase in Temperature.dT, while pressure remains constant Here gamma=1/V=(dV)/(dT) What will be the nature of the graph between gamma and l?

An ideal gas is initially at temperature T and volume V. Its volume in

1.	An ideal gas is initially at temperature T and volume V. Its volume increases by DV due to an increase in Temperature.dT, while pressure remains constant Here gamma=1/V=(dV)/(dT) What will be the nature of the graph between gamma and l?
Answer» Solution :In CASE an ideal gas `pV=RT or ,V=(RT)/p` When pressure remains CONSTANT, we have `(DV)/(dT)=R/P` `thereforegamma=1/V(dV)/(dT)=1/VR/P=R/(RT)=1/T` i.e., `gamma T=1`=constant So the graph `gamma-T` will be a rectangular HYPERBOLA [Fig.6.20]