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An ideal fluid through a pipe of circular cross-section made of two sections with diameters `2.5 cm` and `3.75 cm`. The ratio of the velocities in the two pipes isA. `9:4`B. `3:2`C. `sqrt(3):sqrt(2)`D. `sqrt(2) : sqrt(3)` |
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Answer» Correct Answer - A According to equation of continuity `A_(1)v_(1) = A_(2)v_(2)` `(v_1)/(v_2) = (A_2)/(A_1) = (pi D_(2)^(2)//4)/(pi D_(1)^(2)//4) = ((D_2)/(D_1))^(2)` Here, `D_(1) = 2.5 cm, D_(2) = 3.75 cm` `:. (v_1)/(v_2) = (3.75/2.5)^(2) = (3/2)^(2) = 9/4`. |
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