Saved Bookmarks
| 1. |
An ideal coil of 10H is connected in series with a resistance of `5(Omega)` and a battery of 5V. 2second after the connections is made, the current flowing in ampere in the circuit isA. `(I-e)`B. `e`C. `e^(-1)`D. `(I-e^(-1))` |
|
Answer» Correct Answer - D `I_(0) = (E)/(R ) = 1A , tau = (L)/(R ) = (10)/(5) = 2s, :. (I = 1-e^(-1))A` |
|