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An ice skater moving at 10m//s comes to a halt in 100m on a ice surface. Calculate the coefficient of friction between the ice and the skater ? |
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Answer» Solution :`U=10m//s`, `v=0`, `s=100m` `a=(v^(2)-u^(2))/(2s)=(0-100)/(2xx100)=-0.5ms^(-2)` Reaction force `=R=mg=mxx9.8N` COEFFICIENT of FRICTION `=mu=(F)//(R )=(ma)/(mg)=(a)/(G)=(0.5)/(9.8)=0.05` |
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