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An experiment was set up with the circuit diagram shown figure.Given that R1 = 10Ω,R2 = R3 = 5Ω,r = 0 and E = 5 V(1) The points with the same potential are -(a) b,c,d(b) f,h,j(c) d,e,f(d) a,b,j(2) The current through branch bg is -(a) 1 A(b) \(\frac{1}{3}\)A(c) \(\frac{1}{2}\)A(d) \(\frac{2}{3}\)A(3) The power dissipated in R1 is -(a) 2 W(b) 2.5 W(c) 3 W(d) 4.5 W(4) The potential difference across R3 is -(a) 1.5 V(b) 2 V(c) 2.5 V(d) 3 V |
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Answer» (1). (b) f,h,j (2). (c) \(\frac{1}{2}\)A (3). (d) 4.5 W (4). (c) 2.5 V |
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