1.

An examination was held in two parts of the 630 examiners, 3/10 appeared in only the farst part and 2/15 appeared in only the second part the rest appeared in both the parts. find the number of examineees. who appeared in both the parts.

Answer» EXAMINERS APPEARED in FIRST part only=3/10*630
=189
Examiners appeared only in SECOND part =2/15*630=84
Thus examiners appeared in both=630-(189+84)=630-273=357...
Hope this helps you....


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