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An ester has a molecular weight of 102. On aqueous hydrolysis, it produces a monobasic acid and an alcohol, If 0.185g of the acid produced completely neutralises 25mL of 0.1N NaOH, find out the structural formulae of the produced alcohol, acid and the ester. |
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Answer» Solution :Let the equivalent weight of the acid formed be E. m.e. of the acid= m.e. of NaOH `(0.185)/(E ) xx 1000= 0.1 xx 25` or `E=74` As the acid is monobasic, its MOLECULAR weight is 74. Thus the reaction sequence MAY be represented as `underset("ethyl propionate")(C_(2)H_(5)COOC_(2)H_(5)) overset("HYDROLYSIS")RARR underset("(mol. wt. =74)propionic acid")(C_(2)H_(5)COOH) + underset("ethyl alcohol")(C_(2)H_(5)OH)` |
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