An equimolar mixture of CO_(2 (g)) and CF_(4 (g)) was taken in an empty flask at a particular temperature. These gases reacts as: CO_(2 (g)) + CF_(4 (g)) hArr 2 COF_(2 (g)) After this , mixture attains equilibrium and mole fraction of COF_(2 (g)) was found to be 0.2, then Which of the following will increase concentration of COF_(2 (g)) at equilibrium

An equimolar mixture of CO_(2 (g)) and CF_(4 (g)) was taken in an empt

1.	An equimolar mixture of CO_(2 (g)) and CF_(4 (g)) was taken in an empty flask at a particular temperature. These gases reacts as: CO_(2 (g)) + CF_(4 (g)) hArr 2 COF_(2 (g)) After this , mixture attains equilibrium and mole fraction of COF_(2 (g)) was found to be 0.2, then Which of the following will increase concentration of COF_(2 (g)) at equilibrium
Answer» DECREASE in TEMPERATURE increase in total pressure Addition of inert gas at constant pressure A and B both Solution :For increasing concentration of `COF_(2 (g))` at equilibrium (A) Reaction is exothermic in FORWARD direction hence, decrease in temperature, increase concentration of `COF_(2 (g))` at equilibrium. (b) Total pressure increase, volume DECREASES and hence concentration increases.