1.

An equilibrium mixture for the reaction 2H_(2)S_((g))iff2H_(2(g))+S_(2(g)) had one mole of hydrogen sulphide, 0.2 mole of H_(2) and 0.8 mole of S_(2) in a 2 litre vessel. The value of K_(c ) in mole "litre"^(-1) is

Answer»

`0.004`
`0.016`
`0.080`
`0.032`

SOLUTION :`K=((0.2//2)^(2)(0.8//2))/((1//2)^(2))=((0.1)^(2)(0.4))/((0.5)^(2))=0.016`


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