An equilateral triangle is inscribed in an ellipse whose equation is x2+4y2=4. One vertex of the triangle is (0,1), one altitude is contained in the y−axis, and the length of each side is √mn, where m and n are relatively prime positive integers. Then the value of (m+n) is

An equilateral triangle is inscribed in an ellipse whose equation is x

1.	An equilateral triangle is inscribed in an ellipse whose equation is x2+4y2=4. One vertex of the triangle is (0,1), one altitude is contained in the y−axis, and the length of each side is √mn, where m and n are relatively prime positive integers. Then the value of (m+n) is
Answer» An equilateral triangle is inscribed in an ellipse whose equation is $x^{2} + 4 y^{2} = 4.$ One vertex of the triangle is $(0, 1)$ , one altitude is contained in the $y -$ axis, and the length of each side is $\sqrt{\frac{m}{n}},$ where $m$ and $n$ are relatively prime positive integers. Then the value of $(m + n)$ is