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An equilateral triangle ABC is inscribed in a circle with centre O. Find ∠ AOB and ∠ OBA

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Step-by-step explanation:

⇒   △ABC is an equilateral triangle inscribed in a CIRCLE with center O.

⇒  ∠ABC=∠BCA=∠CAB=60o    [ Angles of equilateral triangle ]

⇒  We KNOW that, ANGLE SUBTENDED at the center of a circle is DOUBLE angle at any point on circumference of circle.

∴    ∠BOC=2∠CAB

∴    ∠BOC=2×60o

∴    ∠BOC=120o



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