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An engine operating between 150^(@)C and 25^(@)C takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine is |
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Answer» 147.7 J Q=500 J `(W)/(Q)=(T_(2)-T_(1))/(T_(2)), W=500((423-298)/(423))=147.7 J`. |
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