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An engine is rotating at the rate of 1500 RPM. Find its angular velocity 57.1 rad/secnone of above257.1 rad/sec1571 rad/sec |
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Answer» AnswerDeceleration can be FOUND by using the equation of motionω=ω 0 +αt⟹α=− tω 0 =− 15×60100 rev/s 2 =− 91 rev/s 2 Now using the equation of MOTION:ω 2 −ω 02 =2αθ⟹θ= 2αω 02 =12.5 |
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