An engine delivered power of 30 kW to a car of mass 1250 kg and velocity of 30 m/s . If the friction force of surface is 750N what will be the maximum acceleration of car ?

An engine delivered power of 30 kW to a car of mass 1250 kg and veloci

1.	An engine delivered power of 30 kW to a car of mass 1250 kg and velocity of 30 m/s . If the friction force of surface is 750N what will be the maximum acceleration of car ?
Answer» <P>`1/3ms^(-2)` `1/4 ms^(-2)` `1/5 ms^(-2)` `1/6 ms^(-2)` Solution :P = 30 kW , m = 1250 kg , v = 30 m/s Resistive FORCE = 750 N Force exerted by engine , `F =P/v =(30,0000)/30 = 1000 N ` maximum acceleration produced ` = ("Force exerted by engine " - " Resistious force ")/("mass of CAR")` ` a = (1000- 750)/1250 = 250/1250 =1/5 m//s^(2)`