An engine consumes 20 kg of fuel per hour. The calorific value of the fuel is 12 Kcal g^(-1). Calculate the efficiency of the engine if the power of the engine is 42 kW.

An engine consumes 20 kg of fuel per hour. The calorific value of the

1.	An engine consumes 20 kg of fuel per hour. The calorific value of the fuel is 12 Kcal g^(-1). Calculate the efficiency of the engine if the power of the engine is 42 kW.
Answer» Solution :CALORIFIC value `= 12xx 10 ^(6) CAL //kg.` Input power `= 240 xx 4.6 // 60 xx 60 W` OUTPUT power `= 42 xx 10 ^(3) W. ` Efficiency = output/input `= 0.15=15%`