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| 1. |
An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Then A. Electric field near A in the cavity = electric field near b in the cavityB. Charge density at A = Charge density at BC. Potential at A = Potetial at BD. Total electric field flux through the surface of the cavity is `q//epsi_(0)`. |
| Answer» Correct Answer - C | |