An elevator is accelerating down at 2m/s^(2) in which a simple pendulum is suspended on one of its vertical wall with string length 2m .The string is pulled aside and bob is held horizontally with string tight.The minimum downward speed (in m/s) with which bob is to be thrown so that bob completes the vertical circle is given by 4sqrt(k) .Then value of k is :

An elevator is accelerating down at 2m/s^(2) in which a simple pendulu

1.	An elevator is accelerating down at 2m/s^(2) in which a simple pendulum is suspended on one of its vertical wall with string length 2m .The string is pulled aside and bob is held horizontally with string tight.The minimum downward speed (in m/s) with which bob is to be thrown so that bob completes the vertical circle is given by 4sqrt(k) .Then value of k is :
Answer» APPLYING the energy conservation principle. The KINETIC energy provided will CHANGE into gravitational potential energy i.e.21 MV 2 =mgl⇒v= 2gl Explanation:I am not sure about it

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