An elevator descends into a mine shaft at therate of 6 m/min. What wil

1.	An elevator descends into a mine shaft at therate of 6 m/min. What will be its positionafter one hour? If it begins to descend from20 m above the ground, what will be itsposition after 45 minutes? 12
Answer» Answer: 1m=6m 1h=660=360 1h and 20M above ground=660-30=330m 45 min=45*6-20=240m Hope it helps Please MARK as BRAINLIEST

An elevator descends into a mine shaft at therate of 6 m/min. What will be its positionafter one hour? If it begins to descend from20 m above the ground, what will be itsposition after 45 minutes? 12

Answer»

Answer:

1m=6m

1h=6*60=360

1h and 20M above ground=6*60-30=330m

45 min=45*6-20=240m

Hope it helps