An elevator descends into a mine shaft at the rate of 5 metre per minu

1.	An elevator descends into a mine shaft at the rate of 5 metre per minute. What will be its position after one hour? If it begins to descend from 15 metre above the ground, what will be its position after 45 minutes?
Answer» Answer: DISPLACEMENT from initial position = VELOCITY X Time = -5 m/min x 45 min = -225 m. Step-by-step EXPLANATION: I hope you like the answer

An elevator descends into a mine shaft at the rate of 5 metre per minute. What will be its position after one hour? If it begins to descend from 15 metre above the ground, what will be its position after 45 minutes?

Answer»

Answer:

DISPLACEMENT from initial position = VELOCITY X Time = -5 m/min x 45 min = -225 m.

Step-by-step EXPLANATION:

I hope you like the answer