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An elevator descends into a mine shaft at the rate of 12 m/min. If the descent starts from 20 m above the ground level, how long will it take to reach – 460 m.answer it plaess |
Answer» EXPLANATION.An elevator DESCENDS into a mine shaft at the rate = 12m/min. if the descends starts from 20 m above the ground level. How long will it take to REACH -460m.According to the question,TOTAL distance elevator has to travel => initial position - Final position => 20 - ( - 460 ) => 480 m Now, elevator descends at rate of = 12 m/min elevator travel = 12 m/min = 1 min elevator travel 1 m = 1/12 min elevator travel = 460 = 1/12 X 480 => 40 it will take = 40 minutes |
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