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an elevator decends into a mine shaft at the rate of 6m/min. if the decent starts starts from 10m above the ground level, how long will it take to reach 350 level |
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Answer» Step-by-step explanation: Distance DESCENDED is denoted by a negative integer, Initial height =+10 m Final Depth =−350 m Total distance to be descended by the elevator =(−350)−(+10)=−360 m Given, the time is TAKEN by the elevator to descend −6 m=1 minute Thus, time taken by the elevator to descend −360 m= (−6) (−360)
------- [from the formula : SPEED= time distance
] =60 minutes hope it helps mark me brainliest like it and follow me TOOO.......... |
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