1.

An element X has the following isotopic composition, 200 X : 90% . 199 X: 8.0% , 202 X : 2.0%.The weighted average atomic mass of the naturallyoccurring element X is closest to:​

Answer»

average ATOMIC mass=200*90+199*8+202*2/100=19996/100=199.96average atomic mass is nearly EQUALS to 200 amu



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