1.

An element X has the following isotopic composition.""^(200)X=90%, ""^(199)X=8.0%, ""^(202)X=2.0%Its average atomic mass is

Answer»

199amu
200amu
201 AMU
202amu

Solution :Average ATOMIC MASS of X
`=0.9xx200+0.08xx199+0.02xx202`
`=180+15.92+404=199.96`
`=200` amu


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