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An element ` ""_(x)A^(y)` emits ` 5 alpha and 4 beta` paricles to give ` ""_(82)B^(207)`. The number of protons and neutrons in A are respectivelyA. ` 88,227`B. 88139C. 82227D. 84139 |
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Answer» Correct Answer - B `""_(x)A^(y) to ""_(82)B^(207) +5_(2)He^(4) +4""_(-1)beta^(0)` On comparing , ` x= 82+5xx2+4(-1)=88` `y= 207+5xx4+4xx0` `= 227` In `""_(88)A^(227)` the number of protons = 88 the number of neutrons =227-88=139 |
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