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An element with molar mass 2.7 xx 10^(-2) "kg mol"^(-1) forms a cubic unit cell with edge length 405 pm. If its density is 2.7 xx 10^3 "kg m"^(-3), what is the nature of the cubic unit cell ? |
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Answer» Solution :Molar Mass (M) `= 2.7 xx 10^(-2) "kg mol"^(-1)` Edge length of a UNIT cell = 405 pm ` = 4.05 xx 10^(-10) m` Density of unit cell = `2.7 xx 10^3 "kg m"^(-3)` Using formula `d = (Z xx M)/(a^3 xx N_A)` we get , `Z = (2.7 xx 10^(3) xx 6.022 xx 10^(23) xx (4.05 xx 10^(-10))^3)/(2.7 xx 10^(-2))` Z = 4. Hence, unit cell is face-centred CUBIC. |
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