1.

An element with density 11.2 g cm^(-3) forms a fcc lattice with edge length of 4 xx 10^(-8) cm. Calculate the atomic mass of the element. [Given : N_(A) = 6.022 xx 10^(23)"atoms" mol^(-1)]

Answer»

SOLUTION :Use the relation
`d=(zM)/(a^(3)N_(A)) or M=(da^(3)N_(A))/(z)`
Here, z = 4 (for fcc CRYSTAL), `d=11.2" G cm"^(-3) and a=4XX10^(-8)cm`
Substituting the VALUES in the above equation, we have
`M=(11.2xx(4xx10^(-8))^(3)xx6.022xx10^(23))/(4)=(11.2xx64xx10^(-24)xx6.022xx10^(-23))/(4)`
`=(11.2xx64xx6.022)/(4xx10)=107.9u`


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