An element undergoes a reaction as shown : X+e^(-) to X^(-) Energy released =30.876 eV The energy released, is used to dissociate 8 g of H_2 molecules equality into H^+ and H^*, where H^* is in an excited state, in which the electron travels a path length equal to four times its debroglie wavelength. (a)Determine the least amount (moles) of 'X' that would be required. Given : I.E. of H =13.6eV/atom Bond energy of H_2 =4.526 eV/molecule. (b) Why is the amount of X calculated in the above question 'least' /

An element undergoes a reaction as shown : X+e^(-) to X^(-) Energy re

1.	An element undergoes a reaction as shown : X+e^(-) to X^(-) Energy released =30.876 eV The energy released, is used to dissociate 8 g of H_2 molecules equality into H^+ and H^, where H^ is in an excited state, in which the electron travels a path length equal to four times its debroglie wavelength. (a)Determine the least amount (moles) of 'X' that would be required. Given : I.E. of H =13.6eV/atom Bond energy of H_2 =4.526 eV/molecule. (b) Why is the amount of X calculated in the above question 'least' /
Answer» SOLUTION :(a)`X+e^(-)TOX^(-)` ENERGY released`=E.A_1=30.87` eV/atom Let no of MOLES of X be a `:. axxN_Axx30.87=4xxN_Axx4.526+4xxN_Axx13.6+4xxN_Axx12.75 implies a=4` moles