An element is found in nature in two isotopic forms with atomic number

1.	An element is found in nature in two isotopic forms with atomic number (A-1) and (A-3). If the average atomic mass is found to be A, then find the relative abundance of the heavier isotope.
Answer» ANSWER: The solution is laid out like this: (EXACT WEIGHT of isotope #1) (ABUNDANCE of isotope #1) + (exact weight of isotope #2) (abundance of isotope #2) = average atomic weight of the element HOPE IT HELPED U DUDE..✌️✌️

An element is found in nature in two isotopic forms with atomic number (A-1) and (A-3). If the average atomic mass is found to be A, then find the relative abundance of the heavier isotope.

Answer»

The solution is laid out like this:

(EXACT WEIGHT of isotope #1) (ABUNDANCE of isotope #1) + (exact weight of isotope #2) (abundance of isotope #2) = average atomic weight of the element

HOPE IT HELPED U DUDE..✌️✌️

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An element is found in nature in two isotopic forms with atomic number (A-1) and (A-3). If the average atomic mass is found to be A, then find the relative abundance of the heavier isotope.​

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An element is found in nature in two isotopic forms with atomic number (A-1) and (A-3). If the average atomic mass is found to be A, then find the relative abundance of the heavier isotope.