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An element having atomic mass 63.1 g/mol has face centred cubic unit cell with edge length 3.608xx10^(-8)cm. Calculate the density of unit cell. [Given : NA=6.022xx1023" atoms/mol"]. |
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Answer» Solution :GIVEN M = 63.1 g/mol `Z=4` `a=3.609xx10^(-8)cm` `N_(A)=6.023xx10^(23)` `"DENSITY "=(zxxM)/(a^(3)xxN_(a))` `=(4xx63.1)/((3.608xx10^(-8))xx6.022xx10^(23))` `=8.924g//cm^(3)` |
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