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An element crystallizes in a structure having fcc unit cell of an edge 200 pm. Calculate the density if 200 g of this element contains 24 xx 10^(23) atoms. |
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Answer» SOLUTION :Edge length = 200 pm Volumne of the unit cell `= (200 xx 10^(-10) cm)^(3)` `= 8 xx 10^(-24) cm^(3)` In a fcc unit cell there are four atoms PER unit cell. Mass of unit cell = `(200 xx 4)/(24 xx 10^(23))` `= 33.3 xx 10^(-23)` g Density `= ("Mass of unit cell")/("VOLUME of unit cell")` `= (33.3 xx 10^(-23) g)/(8 xx 10^(-24) cm^(3))` = 41.6 g `cm^(-3)` |
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