1.

An element (at. mass = 60) having face centred cubic unit cell has a density of 6.23g cm^(-3). What is the edge length of the unit cell? (Avogadro's constant = 6.023 xx 10^(23) mol^(-1))

Answer»


SOLUTION :M=60, Z = 4 for fcc unit cell, d=6.23 g `cm^(-3)`, `N_A = 6.023 XX 10^(23) mol^(-1), d = (ZM)/(Ν_Α xx a^3)`
`a^3=(4 xx 60)/(6.023 xx 10^(23) xx 6.23) cm^3 = 6.396 xx 10^(-23) cm^3`,
`a = 4 xx 10^(-8)` cm = 400 PM


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