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An electron orbiting around a nucleus has angular momentum L. The magnetic field produced by the electron at the centre of the orbit can be expressed as :A. `B = (mu_(0) e//8pi mr^(3))L`B. `B =(mu_(0)e//4 pi mr^(3))L`C. `B = (mu_(0) e//pi mr^(3))L`D. `B =(e//4 pi epsilon_(0) mr^(3))L` |
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Answer» Correct Answer - B `(B)/(L)=(mu_(0))/(4 pi)((eV)/(r^(2)))/(mVr)L=m Vr` `(B)/(L)=(mu_(0))/(4pi)(eV)/(e^(2))xx(1)/(mVr)` `rArr B =(mu_(0))/(4 pi)(L)/(r)=(mu_(0)eL)/(4 pimr^(3))`. |
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