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An electron of mass `m` and a photon have same energy `E`. The ratio of de - Broglie wavelengths associated with them is :A. `1/C(E/(2m))^(1/2)`B. `(E/(2m))^(1/2)`C. `C(2mE)^(1/3)`D. `1/(xC)((2m)/E)^(1/2)` |
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Answer» Correct Answer - A `lambda_(e)=h/(sqrt(2mE)), lambda_(p)=(hc)/E` `(lambda_(e))/(lambda_(p))=1/(sqrt(2mE)). E/C=1/C(E/(2m))^(1/2)` |
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