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An electron of mass `m` and a photon have same energy `E`. The ratio of de - Broglie wavelengths associated with them is :A. `sqrt((2 mc^(2))/(E))`B. `sqrt((mc^(2))/(E))`C. `(2 mc^(2))/(E)`D. `(mc^(2))/(E)` |
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Answer» Correct Answer - A For an electron with kinetic energy E : `lamda = (h)/(sqrt(2mE))` an for a photon `lamda = (hc)/(E)` `:.` Ratio `=(hc)/(E).(sqrt(2mE))/(h)=sqrt((2mc^(2))/(E))` |
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