1.

an electron is moving with a velocity of 2.5*10^6 m/s . if the uncertainty in its velocity is 0.1% calculate the uncertainty in its position

Answer»

Explanation:According to Heisenberg's UNCERTAINITY PRINCIPLE, velocity of electron, v = 2.5 ×10⁶ ms⁻¹Planck's constant, h=6.623×10⁻³⁴ Js Mass of electron, me=9.1×10⁻³¹ kgΔv = 2.5 * 10⁶ * 0.1 / 100 = 2500 ms⁻¹=> uncetainity position when n = 4 is, Δx = h/nπ * 1/ me*Δv= 6.626 * 10⁻³⁴/4π * 1/ 9.1×10⁻³¹ * 2500= 2.3 * 10⁻⁸ metre=> As the VALUE of "n" varies in above equation, the value the uncertainity position is also varies.



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