1.

an electron is moving on the third bohr Orbit calculate the energy of the electron given the energy of the first bohr orbit is 13.6 electron volt

Answer»

1.51 eVExplanation:E = 13.6 × z^2 / n^2Given that E in the first SHELL is 13.6 eV Therefore it is evident that z(atomic NUMBER ) is 1Therefore ,E(3) = 13.6 /9 =1.51 eV



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