1.

An electron is moving in a circle of radius r in a uniform magnetic field B. Suddenly the field is reduced to B/2. The radius of the circular path now becomes.

Answer»

`r/2`
2R
`r/4`
4r

Solution :Radius of CIRCULAR path :
`r=(mv)/(qB)rArrrprop1/B`
When B is REDUCED to `B/2`, r is doubled
`therefore` NEW radius of circular path is 2r


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