An electron is an excited state of `Li^(2 + )`ion has angular momentum `3h//2 pi ` . The de Broglie wavelength of the electron in this state is `p pi a_(0) (where a_(0) ` is the bohr radius ) The value of p is

An electron is an excited state of `Li^(2 + )`ion has angular momentum

1.	An electron is an excited state of `Li^(2 + )`ion has angular momentum `3h//2 pi ` . The de Broglie wavelength of the electron in this state is `p pi a_(0) (where a_(0) ` is the bohr radius ) The value of p is
Answer» Correct Answer - `2` `L=(nh)/(2pi)=(3h)/(2pi)` `n=3` `lambda=(h)/(p)=(h)/(mv)=(h2pir)/(3h)=(2pir)/(3)` `r=a_(0)(n^(2))/(Z)` `lambda=(2pi)/(3)a_(0)(n^(2))/(Z)=(2pi)/(3)a_(0)(3^(2))/(3)=2pia_(0)`

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An electron is an excited state of `Li^(2 + )`ion has angular momentum `3h//2 pi ` . The de Broglie wavelength of the electron in this state is `p pi a_(0) (where a_(0) ` is the bohr radius ) The value of p is

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