An electron is accelerated through a potential difference of 500 V. It

1.	An electron is accelerated through a potential difference of 500 V. Its de Broglie wavelength would be
Answer» h=planks CONST =6.6×10^-34 Mass of ELECTRON =9.1×10-31 Voltage= 500 Wavelength (W) = h/√2mKE = h/√2meV =6.6×10^-34/√2×9.1×10-31×500 =6.6×10^-34/√910×10-30 =6.6×10^-34/30.1×10-15 =0.219×10-19 I HOPE this HELPS ( ╹▽╹ )

An electron is accelerated through a potential difference of 500 V. Its de Broglie wavelength would be

Answer»

h=planks CONST =6.6×10^-34

Mass of ELECTRON =9.1×10-31

Voltage= 500

Wavelength (W)

= h/√2mKE

= h/√2meV

=6.6×10^-34/√2×9.1×10-31×500

=6.6×10^-34/√910×10-30

=6.6×10^-34/30.1×10-15

=0.219×10-19

I HOPE this HELPS ( ╹▽╹ )

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An electron is accelerated through a potential difference of 500 V. Its de Broglie wavelength would be

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