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An electron in the hydrogen atom jumps from excited state `n` to the ground state. The wavelength so emitted illuminates a photo-sensitive material having work function `2.75eV`. If the stopping potential of the photoelectron is `10V`, the value of `n` isA. 3B. 4C. 5D. 2 |
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Answer» Correct Answer - B `KE_(max) =10eV` `phi =2.75 eV` `E = phi+ KE_(max) = 12.75 eV` = Energy difference between `n =4 and n = 1 (n = 4)` `rArr` value of `n = 4` |
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