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An electron and proton are possessing same amount of kinetic energy. Which of the two has greater de Broglie wavelength ?

Answer»

Solution :de Brogile WAVELENGTH `LAMBDA = h/sqrt(2mE)` where E is the kinetic energy of a particle of mass m. Given that E is same for electron and proton. So, `lambda prop 1/sqrtm`. HENCE,`lambda` will be GREATER for smaller mass. Thus, de Broglie wavelength is greater for an electron.


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