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An electron, an alpha-particle, and a proton have the same kinetic energy. Which of these particles has the shortest de Broglie wavelength? |
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Answer» Solution :For a particle, DE Broglie wavelength, `lambda=h//p` Kinetic energy, `K=p^(2)//2m` Then, `lambda=h//sqrt(2mk)` For the same kinetic energy K, the de Broglie wavelength ASSOCIATED with the particle is inversely proportional to the square ROOT of their masses. A proton `(""_(1)^(1)H)` is 1836 times massive than an electron and an `ALPHA`-particle `(""_(2)^(4)He)` four times that of a proton. Hence, `alpha-` particle has the shortest de Broglie wavelength |
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